2n^2+18n+28=0

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Solution for 2n^2+18n+28=0 equation:



2n^2+18n+28=0
a = 2; b = 18; c = +28;
Δ = b2-4ac
Δ = 182-4·2·28
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-10}{2*2}=\frac{-28}{4} =-7 $
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+10}{2*2}=\frac{-8}{4} =-2 $

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